\(\left( t _{1 / 2}\right)_{250 \text { torr }}=4\,min\)
\(t _{1 / 2} \propto a ^{1- n }\)
As \(t _{1 / 2}\) is independent of initial pressure. Hence, order is \(1^{st}\) order.
${I_2}\,\underset{{{K_{ - 1}}}}{\overset{{{K_1}}}{\longleftrightarrow}}\,2I\,$ (fast step)
$2I + {H_2}\xrightarrow{{{K_2}}}2HI$ (slow step)
તો પ્રક્રિયાનો વેગનિયમ જણાવો.
$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
સાચો વિકલ્પ કયો છે ?