\(\,8\,\,\frac{4}{3}\,\,\pi {r^3}\,\, = \,\,\frac{4}{3}\,\,\pi {R^3}\,\, \Rightarrow \,\,2r\,\, = \,\,R\)
\({V_{tiny}}\,\, = \,\,\frac{{kq}}{r}\,\,\therefore \,\,{V_{big}}\,\, = \,\,\frac{{k\,\, \times \,\,8q}}{R}\,\, = \,\,\frac{{8kq}}{{2r}}\)
\({V_{big}}\,\, = \,\,4{V_{tiny}}\,\, = \,\,4\,\, \times \,\,10\,\, = \,\,40\,V\)
(પદાર્થનો ડાયઈલેક્ટ્રીક અચળાંક $=3.2$) (નજીકત્તમ પૂર્ણાંકમાં ગણો)