b
$\frac{{PV}}{T} = R$
$\Rightarrow$ $\frac{{{P_1}{V_1}}}{{{T_1}}} = \frac{{{P_2}{V_2}}}{{{T_2}}}$
$\Rightarrow$ $\frac{{200 \times V}}{{(273 + 22)}} = \frac{{{P_2} \times 1.02V}}{{(273 + 42)}}$ $({V_2} = V + 0.02V)$
$\Rightarrow$ ${P_2} = \frac{{200 \times 315}}{{295 \times 1.02}} = 209\,kPa$