An electron having mass $m$ and kinetic energy $K$ enter in uniform magnetic field $B$ perpendicularly, then its frequency will be
AIPMT 2001, Medium
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$\frac{ mv ^{2}}{ r }= qV B$
$\frac{ mv }{ r }= qB$
$m\omega = qB$
$\omega = qB / m$
$f =\frac{ qB }{2 \pi m }$
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