An ideal gas has volume ${V_0}$ at ${27^o}C.$ It is heated at constant pressure so that its volume becomes $2{V_0}.$ The final temperature is
Easy
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Given below are two statementView Solution
Statement $-I$ : What $\mu$ amount of an ideal gas undergoes adiabatic change from state $\left( P _{1}, V _{1}, T _{1}\right)$ to state $\left( P _{2}, V _{2}, T _{2}\right)$, the work done is $W =\frac{1 R \left( T _{2}- T _{1}\right)}{1-\gamma}$, where $\gamma=\frac{ C _{ P }}{ C _{ V }}$ and $R =$ universal gas constant,
Statement $-II$ : In the above case. when work is done on the gas. the temperature of the gas would rise.
Choose the correct answer from the options given below
- 2An ideal gas undergoes cyclic process as shown in density pressure graph. During the process $AB$ the work done $|W_{AB}| = 70\,J$ . During the process $BC$, the gas absorbs $150\,J$ of heat. During the process $CA$ , gas undergoes expansion and does $210\,J$ of workView Solution
- 3$300 \,cal$. of heat is given to a heat engine and it rejects $225 \,cal$. of heat. If source temperature is $227^{\circ} C$, then the temperature of sink will be____${ }^{\circ} C$.View Solution
- 4View SolutionA cycle tyre bursts suddenly. This represents an
- 5Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason $R$. Assertion A : Efficiency of a reversible heat engine will be highest at $-273^{\circ} C$ temperature of cold reservoir.View Solution
Reason $R$ : The efficiency of Carnot's engine depends not only on temperature of cold reservoir but it depends on the temperature of hot reservoir too and is given as $\eta=\left(1-\frac{ T _2}{ T _1}\right)$.
In the light of the above statements, choose the correct answer from the options given below
- 6Following figure shows two processes $A$ and $B$ for a gas. If $\Delta Q_A$ and $\Delta Q_B$ are the amount of heat absorbed by the system in two cases, and $\Delta U_A$ and $\Delta U_B$ are changes in internal energies, respectively, thenView Solution
- 7View SolutionAn ideal diatomic gas is heated at constant pressure. The ratio of the work done to the heat supplied is
- 8'$n$' moles of an ideal gas undergoes a process $A \rightarrow B$ as shown in the figure. The maximum temperature of the gas during the process will beView Solution
- 9View SolutionFirst law thermodynamics states that
- 10The volume of $1\; mole$ of an ideal gas with the adiabatic exponent $\gamma$ is changed according to the relation $V=\frac bT$ where $b =$ constant. The amount of heat absorbed by the gas in the process if the temperature is increased by $\triangle T$ will beView Solution