Avessel with open mouth contains air at 60^oC. When the vessel is heated upto temperature T, one fourth of the air goes out. The value

Q: Avessel with open mouth contains air at $60^oC$. When the vessel is heated upto temperature $T$, one fourth of the air goes out. The value of $T$ is ..... $^oC$

b $M_{1}=M, T_{1}=60+273$ $=333 K, M_{2}$ $=M-\frac{M}{4}=\frac{3 M}{4}$ [As $1/ 4$ th part of air escapes] If pressure and volume of gas remains constant then $\mathrm{MT}=$ constant $\therefore \frac{T_{2}}{T_{1}}=\frac{M_{1}}{M_{2}}=\left(\frac{M}{3 M / 4}\right)=\frac{4}{3} \Rightarrow T_{2}$ $=\frac{4}{3} \times T_{1}=\frac{4}{3} \times 333=444 \mathrm{K}$ $=171^{\circ} \mathrm{C}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Avessel with open mouth contains air at $60^oC$. When the vessel is heated upto temperature $T$, one fourth of the air goes out. The value of $T$ is ..... $^oC$

A$80$
B$171$
C$333$
D$444$

Diffcult

STD 11 Science
NEET
STD 11 - 11. thermodynamics
Physics

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