Given, $\Delta \mathrm{H}=170 \times 10^{3} \mathrm{J}$
$\Delta S=170 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$
Applying, $\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S},$ the value of $\Delta \mathrm{G}=$ -ve only when $\mathrm{T} \Delta \mathrm{S}>\Delta \mathrm{H},$ which is possible only when $\mathrm{T}=1110 \mathrm{K}$
$\Delta G=170 \times 10^{3}-(1110 \times 170)$$=-18700 \mathrm{J}$
Thus, reaction is spontaneous at $\mathrm{T}=1110 \mathrm{K}$
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