(Basic buffer solution)
\(pOH = pK_b + log\) \(\frac{{0.08}}{{0.02}}\)
\(= pK_b + 0.602\)
\(= 3.30 + 0.602= 3.902\)
\(pH = 10.09\)
\([H^+] = 7.99 \times 10^{-11} \approx 8 \times 10^{-11} M\)
(આપેલ : $pK _{ b }\left( NH _3\right)=4.74,NH _3$ નું મોલર દળ $=17\, g\, mol ^{-1},NH _4 Cl$નું મોલર દળ $= 53.5\, g\, mol ^{-1}$