Question
Consider the cell reaction of an electrochemical cell:
$\text{Ni}\text{(s)}+2\text{Ag}^+\text{(aq)}\xrightarrow{\ \\ \ \ \ \ }\text{Ni}^{2+}\text{(aq)}+2\text{Ag}\text{(s)}$
Answer the following questions:
  1. Write anode and cathode half reactions.
  2. Mention the direction of flow of electrons.
  3. How is the electroneutrality maintained in solution of two half cells?
  4. Write the formula for calculating standard e.m.f of this cell.
  5. How does e.m.f. change when concentration of $Ag^+$ is decreased?

Answer

  1. At anode: $\text{Ni}\text{(s)}\xrightarrow{\ \\ \ \ \ \ }\text{Ni}^{2+}\text{(aq)}+2\text{e}^-$
At cathode: $2\text{Ag}^+\text{(aq)}+2\text{e}^-\xrightarrow{ \ \ \ \ \ \ }2\text{Ag}\text{(s)}$
  1. Electrons will flow from nickel to silver i.e. anode to cathode.
  2. Salt bridge contains $KCI, K^+ $ will neutralize negative ion in cathodic half cell and $Cl^-$ will neutralise $Ni^2​​​​​​​^+​​​​​​​$ in anodic half cells to maintain electroneutrality.
  3. $\text{E}^\circ_\text{cell}=\text{E}^\circ_\text{cathode}-\text{E}^\circ_\text{anode}$
  4. E.M.F of cell will decrease when concentration of $Ag^+$​​​​​​​​​​​​​​ is decreased.

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