So, for the reduction of a metal oxide, \(\Delta G\) value must be negative, and this can only be achieved among all given possibilities of \(\Delta H\) and \(T \Delta S\) values, when the \(\Delta H =- ve\) and \(T \Delta S =+ ve\) at any temperature.
$(I)\, q + W \,\,(II)\, q \,\,(III) \,W \,\,(IV)\, H - TS$