MCQ
$\frac{{dy}}{{dx}} = x\log x$ નો ઉકેલ મેળવો.
- A$y = {x^2}\log x - \frac{{{x^2}}}{2} + c$
- B$y = \frac{{{x^2}}}{2}\log x - {x^2} + c$
- C$y = \frac{1}{2}{x^2} + \frac{1}{2}{x^2}\log x + c$
- ✓એકપણ નહી.
==> $\int_{}^{} {dy = } \int_{}^{} {x\log xdx} $ ==>$y = \frac{{x^2}}{{2}} log\ x - \frac{{x^2}}{{4}} + c$.
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