\(P_\rho=30(2)=60 \,kg ms ^{-1}\)
\(P_Q=40(2)=80 \,kg ms ^{-1}\)
\(\tan \theta=\frac{60}{80}=3 / 4\)
\(\theta=37^{\circ}\)
So angle between \(P\) and \(R\) will be \(90^{\circ}+37^{\circ}=127^{\circ}\)
$\text { ( } g=10 \mathrm{~m} / \mathrm{s}^2 $ લો.)