Distance moved in 3 sec \( = \frac{9}{2}g\)
Remaining distance \( = \frac{{16}}{2}g\)
If \(t\) is the time taken by the stone to reach the ground for the remaining distance then
\( \Rightarrow \frac{{16}}{2}g = \frac{1}{2}g{t^2} \Rightarrow t = 4\;\sec \)
(જ્યાં $v$ વેગ છે)