Initial concentration Rate of reaction
\(2\times 10^{-3}\,M\) \(2.40\times 10^{-4}\,MS^{-1}\)
\(1\times 10^{-3}\,M\) \(0.60\times 10^{-4}\,MS^{-1}\)
rate of reaction
\(r\,=\,k\,[A]^x\)
where \(x\,=\) order of reaction
hence
\(2.40 \times {10^{ - 4}}\, = \,k\,{[2 \times {10^{ - 3}}]^x}\) ..... \((i)\)
\(0.60 \times {10^{ - 4}}\, = \,k\,{[1 \times {10^{ - 3}}]^x}\) ..... \((ii)\)
on dividing eqn. \((i)\) from eqn. \((ii)\) we get
\(4\,=\,(2)^x\)
\(\therefore \,\,x=2\)
i.e., order of reaction \(=2\)
(લો : $\ln 5=1.6094;\left.R =8.314\, J mol ^{-1} K ^{-1}\right)$
$T$ (in, $K$) $- 769$ , $1/T$ (in, $K^{-1}$ ) $- 1.3\times 10^{-3},$
$\log_{10}K - 2.9\,T$ (in, $K$) $- 667$, $1/T$ (in, $K^{-1}) - 1.5\times 10^{-3}$, $\log_{10}\,K - 1.1$