(આપેલું છે$: \ln 10=2.3, R =8.3 \,J\, K ^{-1} \,mol ^{-1}, \log 2=0.30$ )
\(0.3=\frac{ E _{ a }}{2.303 \times 8.3}\left(\frac{9}{300 \times 309}\right)\)
\(E _{ a }=\frac{0.3 \times 2.303 \times 8.3 \times 300 \times 309}{9}\)
\(=59065.04\, J\)
\(E _{ a }=59.06\, kJ\)
[અહી આપેલ $\left.\log _{10} 2=0.3010\right]$