\(\Phi=\text { flux }=\vec{B} \cdot \vec{A}\)
\(\because \overrightarrow{ B }_{0}>\overrightarrow{ B }_{ i }\)
\(\Phi_{0}=\overrightarrow{ Bo } \cdot \overrightarrow{ A }\)
\(\Phi_{i}=\vec{B}_{i} \cdot \vec{A}\)
Magnetic field B in the circular region is more than outside \(\because \overrightarrow{ B }_{0}>\overrightarrow{ B }_{ i }\)
\(\therefore \Phi_{0}>\Phi_{ i }\)