\(E_{cell}^o = E_{{\rm{cathode}}}^o - E_{{\rm{anode}}}^o\) \(= -0.44 -(-0.14)= -0.30\,V\)
The negative \(EMF\) suggests that the reaction goes spontaneously in reversed direction.
$(i)\, A3^-\rightarrow A^{2-} + e; E° = 1.5 \,V$
$(ii) \,B^{+}+ e \rightarrow B; E° = 0.5 \,V$
$(iii)\, C^{2+} + e \rightarrow C^{+}; E°= 0.5\, V$
$(iv)\, D \rightarrow D^{2+}+ 2e; E° = -1.15\, V$
(આપેલ: $ E^oCr^{+3}| Cr = -0.75 \,V$ $E^o Fe^{+2} | Fe = - 0.45\, V)$