Find force per unit length at $P$.
AIIMS 2019, Medium
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The magnetic field at $B$,
$B=\frac{\mu_{0} i}{4 \pi r}+0+\frac{\mu_{0} i}{4 \pi r}$
$=\frac{\mu_{0} \times 5}{4 \pi \times 5 \times 10^{-2}} \times 2$
$=\frac{\mu_{0}}{4 \pi} \times 200$
$=2 \times 10^{-5} T$
Consider the length of wire element at $P$ is $dl$.
The force per unit length at $P$ is,
$F=i B d l$
$\frac{F}{d l}=i B$
$=5 \times 2 \times 10^{-5}$
$=10^{-4} N / m$
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