Four equal charges $Q$ are placed at the four corners of a square of each side is $'a'$. Work done in removing a charge $-Q$ from its centre to infinity is
AIIMS 1995, Medium
Download our app for free and get started
(c) Potential at centre $O$ of the square
${V_O} = 4\,\left( {\frac{Q}{{4\pi {\varepsilon _0}(a/\sqrt 2 )}}} \right)$
Work done in shifting $(-Q)$ charge from centre to infinity $W = - \,Q({V_\infty } - {V_O}) = Q{V_0}$$ = \frac{{4\sqrt 2 \,{Q^2}}}{{4\pi {\varepsilon _0}a}}$$ = \frac{{\sqrt 2 {Q^2}}}{{\pi {\varepsilon _0}a}}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A charge $+q$ is distributed over a thin ring of radius $r$ with line charge density $\lambda=q \sin ^{2} \theta /(\pi r)$. Note that the ring is in the $X Y$ - plane and $\theta$ is the angle made by $r$ with the $X$-axis. The work done by the electric force in displacing a point charge $+ Q$ from the centre of the ring to infinity isView Solution
- 2Two charge $ + \,q$ and $ - \,q$ are situated at a certain distance. At the point exactly midway between themView Solution
- 3If some charge is given to a solid metallic sphere, the field inside remains zero and by Gauss's law all the charge resides on the surface. Now, suppose that Coulomb's force between two charges varies as $1 / r^{3}$. Then, for a charged solid metallic sphereView Solution
- 4Two insulated charged conducting spheres of radii $20\,cm$ and $15\,cm$ respectively and having an equal charge of $10\,C$ are connected by a copper wire and then they are separated. ThenView Solution
- 5The capacity of a spherical conductor in $ MKS$ system isView Solution
- 6A capacitor has air as dielectric medium and two conducting plates of area $12 \mathrm{~cm}^2$ and they are $0.6 \mathrm{~cm}$ apart. When a slab of dielectric having area $12 \mathrm{~cm}^2$ and $0.6 \mathrm{~cm}$ thickness is inserted between the plates, one of the conducting plates has to be moved by $0.2 \mathrm{~cm}$ to keep the capacitance same as in previous case. The dielectric constant of the slab is : (Given $\left.\epsilon_0=8.834 \times 10^{-12} \mathrm{~F} / \mathrm{m}\right)$View Solution
- 7A parallel plate air capacitor has capacity $C,$ distance of separation between plates is $d$ and potential difference $V$ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor isView Solution
- 8The charge on any one of the $2\,\mu \,F$ capacitors and $1\,\mu \,F$ capacitor will be given respectively (in $\mu \,C$) asView Solution
- 9View SolutionA non uniformly shaped conductor is charged then at it's sharpest point
- 10As in figure shown, if a capacitor $C$ is charged by connecting it with resistance $R$, then energy is given by the battery will beView Solution
