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The temperature of a gas at pressure $P$ and volume $V$ is $27°C.$ Keeping its volume constant if its temperature is raised to $927°C,$ then its pressure will be
Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecule changes from $\tau_{1}$ to $\tau_{2} .$ If $\frac{C_{p}}{C_{v}}=\gamma$ for this gas then a good estimate for $\frac{\tau_{2}}{\tau_{1}}$ is given by :
The root mean square speed of the molecules of a diatomic gas is $v$. When the temperature is doubled, the molecules dissociate into two atoms. The new root mean square speed of the atom is
A container $X$ has volume double that of contianer $Y$ and both are connected by a thin tube. Both contains same ideal gas. The temperature of $X$ is $200\,\,K$ and that of $Y$ is $400\,\,K$. If mass of gas in $X$ is $m$ then in $Y$ it will be:
A gas is enclosed in a vessel at a constant temperature at a pressure of $5$ atmosphere and volume $4$ litre. Due to a leakage in the vessel, after some time, the pressure is reduced to $4$ atmosphere. As a result, the
The variation of pressure $P$ with volume $V$ for an ideal diatomic gas is parabolic as shown in the figure. The molar specific heat of the gas during this process is