From a supply of identical capacitors rated $8\ \mu F$, $250\ V$, the minimum number of capacitors required to form a composite $16$ $\mu F$, $1000$ $V$ is :
A$2$
B$4$
C$16$
D$32$
Medium
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D$32$
d $4$ times in series. Let each be $x$, then
$\frac{x}{4}=16 \mu F \Rightarrow x=4 \mu F$
Which is possible when $8$ are connected in parallel
$\Rightarrow 8 \times 4=32$
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