In a meter bridge, the null point is found at a distance of 40 cm from A. If a resistance of 12 Ω is connected in parallel with S, the null point occurs at 50.0 cm from. Determine the values of R and S.
CBSE DELHI - SET 1 2010
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$\frac{\text{R}}{\text{S}} = \frac{40}{60} = \frac{2}{3}$
$\frac{\text{R}(12 + \text{S})}{12\text{S}} = \frac{50}{50} = 1 $
$\Rightarrow\text{R} = 4 \Omega \text { and }\text{S} = 6 \Omega.$
$\frac{\text{R}(12 + \text{S})}{12\text{S}} = \frac{50}{50} = 1 $
$\Rightarrow\text{R} = 4 \Omega \text { and }\text{S} = 6 \Omega.$
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