Initially a gas of diatomic molecules is contained in a cylinder of volume $V _{1}$ at a pressure $P_{1}$ and temperature $250\, K$. Assuming that $25 \%$ of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature $2000\, K ,$ when contained in a volume $2 V _{1}$ is given by $P _{2}$. The ratio $\frac{P _{2}}{ P _{1}}$ is.
A$5$
B$10$
C$13$
D$9$
JEE MAIN 2020, Medium
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A$5$
a $P V = n R T$
$P _{1} V _{1}= nR\times 250$
$P _{2}\left(2 V _{1}\right)=\frac{5 n }{4} R \times 2000$
Divide
$\frac{ P _{1}}{2 P _{2}}=\frac{4 \times 250}{5 \times 2000}$
$\frac{P_{1}}{P_{2}}=\frac{1}{5}$
$\frac{P_{2}}{P_{1}}=5$
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