MCQ
$\int_0^\pi x \,f\,(\sin x)\,dx = $
- A$\pi \int_0^\pi {f(\sin x)\,dx} $
- ✓$\frac{\pi }{2}\int_0^\pi {f(\sin x)\,dx} $
- C$\frac{\pi }{2}\int_0^{\pi /2} {f(\sin x)\,dx} $
- Dએકપણ નહીં.
Since $\int_0^a {xf(x)dx = \frac{1}{2}a\int_0^a {f(x)dx,} } $
if $f(a - x) = f(x)$.
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