MCQ
જો $f(x) = \left\{ \begin{array}{l}{x^2} + k,\;\;\;\;{\rm{when}}\;\;x \ge 0\\ - {x^2} - k,\;\;{\rm{when\,\, }}x < 0\end{array} \right.$ એ $x = 0$ માટે સતત હોય તો $ k = . . .$
  • $0$
  • B
    $1$
  • C
    $2$
  • D
    $-2$

Answer

Correct option: A.
$0$
a
(a) Here $\mathop {\lim }\limits_{x \to 0 + } \,\,f(x) = k,\,\,\,\mathop {\lim }\limits_{x \to 0 - } f(x) = - k$ and $f(0) = k$

But $f(x)$ is continuous at $x = 0,$ therefore $k$ must be zero.

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