Milli-equivalents of ${Fe}^{2+}=$ milli-equivalents of ${K}_{2} {Cr}_{2} {O}_{7}$
${M} \times 10 \times 1=0.02 \times 15 \times 6$
${M}=0.18=18 \times 10^{-2} \,{M}$
$2VO + 3Fe_2O_3 → 6FeO + V_2O_5 (V = 51, Fe = 56)$
$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
અહી $20\, mL$ of $0.1\, M\, KMnO_4$ એ કોના બરાબર હશે