$[$આણ્વિય દળ : સિલ્વર $=108$, બ્રોમિન $=80]$
\(\Rightarrow \quad\) Mass of \({Br}=\frac{0.2397}{188} \times 80\, {~g}\)
therefore \(\%\) Br in the organic compound
\(=\frac{W_{\text {Br }}}{W_{T}} \times 100\)
\(=\frac{0.2397 \times 80}{188 \times 0.15} \times 100=0.85 \times 80\)
\(=68\)
\(\Rightarrow\) Nearest integer is \('68^{\prime}\)