: Conductance $( G )=0.55 mS$

: Cell constant $\left(\frac{\ell}{ A }\right)=1.3 cm ^{-1}$

To Calculate : Molar conductivity $\left(\lambda_{ m }\right)$ of sol.

$\rightarrow$ Since $\lambda_{ m }=\frac{1}{1000} \times \frac{ k }{ m }$

$\rightarrow$ Molarity $=5 \times 10^{-3} \frac{ mol }{ L }$

$\rightarrow$ Conductivity $= G \times\left(\frac{\ell}{ A }\right)=0.55 \,mS \times \frac{1.3}{\frac{1}{100}} \,m ^{-1}$

$=55 \times 1.3 \, mSm ^{-1}$

eq $^{ n }(1) \,{\lambda_{ m }}=\frac{1}{1000} \times \frac{55 \times 1.3}{\left(\frac{5}{1000}\right)} \frac{ mSm ^{2}}{ mol }$

$\Rightarrow \lambda_{ m }=14.3 \, \frac{ mSm ^{2}}{ mol }$