\(Pb + Pb{O_2} + 2{H_2}S{O_4}\) \(\underset{{\operatorname{Re} ch\arg e}}{\overset{{Disch\arg e}}{\longleftrightarrow}}\) \(2PbS{O_4} + 2{H_2}O\)
${Zn}({s})+{Cu}^{2+}(0.02 {M}) \rightarrow {Zn}^{2+}(0.04 {M})+{Cu}({s})$
${E}_{\text {cell }}=...... \,\times 10^{-2} \,{~V}$ { (નજીકના પૂર્ણાંકમાં) }
${\left[ {E}_{{Cu} / {Cu}^{2+}}^{0}=-0.34\, {~V}, {E}_{2 {n} / {Zn}^{2+}}^{0}=+0.76 \,{~V}\right.}$
$\left.\frac{2.303 {RT}}{{F}}=0.059\, {~V}\right]$
$Zn(s) + C{u^{2 + }}(0.1\,M) \to Z{n^{2 + }}(1\,M) + Cu(s)$ માટે $E_{cell}^o$ is $1.10\,volt$ હોય તો ${E_{cell}}$ જણાવો. $\left( {2.303\frac{{RT}}{F} = 0.0591} \right)$