[લો; $R =8.314 \,J\, mol ^{-1}\, K ^{-1}$ In $3.555=1.268$]
$T _{1}=303 K ; T _{2}=313 K$
$\frac{ K _{ T _{2}}}{ K _{ T _{1}}}=3.555$
$\ell E (3.555)=\frac{ E _{ a }}{8.314}\left[\frac{1}{303}-\frac{1}{313}\right]$
$E_a=99980.715$
$E _{ a }=99.98 \frac{ kJ }{ mole }$
| Expt. No. | $(A)$ | $(B)$ | પ્રારંભિક દર |
| $1$ | $0.012$ | $0.035$ | $0.10$ |
| $2$ | $0.024$ | $0.070$ | $0.80$ |
| $3$ |
$0.024$ |
$0.035$ | $0.10$ |
| $4$ | $0.012$ | $0.070$ | $0.80$ |