b
બંનેને જાડતી રેખાને અક્ષ તરીકે લેતાં,
\({x_{CM}}\, = \,\,\frac{{{m_1}\, \times \,\,0\,\, + \,\,{m_2}\, \times \,\,L}}{{{m_1}\,\, + \,\,{m_2}}}\,;\,\,\,\,\,\,{y_{CM}}\, = 0\,\,;\,\,\,\)
\({z_{CM}}\, = \,\,0\,\,\,\,\, \Rightarrow \,\,\,{x_{CM}}\,\,\, = \,\,\frac{{{m_2}L}}{{{m_1}\, + \,\,{m_2}}}\)
