d
(d) The image of object at infinity should be formed at \(100\,\,cm\) from the eye

\(\frac{1}{f} = \frac{1}{\infty } - \frac{1}{{100}} = - \frac{1}{{100}}\)

So the power \( = \frac{{ - 100}}{{100}} = - \;1 D\)

(Distance is given in \(cm\) but \(P = \frac{1}{f}\) in metres)