Question
Match the thermodynamic processes taking place in a system with the correct conditions. In the table: $\Delta Q$ is the heat supplied, $\Delta W$ is the work done and $\Delta U$ is change in internal energy of the system
Process Condition
$(I)$ Adiabatic $(A)\; \Delta W =0$
$(II)$ Isothermal $(B)\; \Delta Q=0$
$(III)$ Isochoric $(C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0$
$(IV)$ Isobaric $(D)\; \Delta U =0$

Answer

$(I)$ Adiabatic process $\Rightarrow \Delta Q=0$ No exchange of heat takes place with surroundings

$(II)$ Isothermal proess $\Rightarrow$ Temperature remains constant $(\Delta T =0)$

$\Delta u =\frac{ F }{2} nR \Delta T \Rightarrow \Delta u =0$

No change in internal energy $[\Delta u =0]$

$(III)$ Isochoric process Volume remains constant

$\Delta V =0$

$W =\int P \cdot d V =0$

Hence work done is zero.

$(IV)$ Isobaric process $\Rightarrow$ Pressure remains constant

$W = P . \Delta V \neq 0$

$\Delta u =\frac{ F }{2} nR \Delta T =\frac{ F }{2}[ P \Delta V ] \neq 0$

$\Delta Q = n C _{ p } \Delta T \neq 0$

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