Two moles of helium gas are taken over the cycle $ABCDA$, as shown in the $P-T$ diagram.The work done on the gas in taking it from $D$ to $A$ is
AIEEE 2009, Medium
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Work done by the system in the isothermal process
$DA\,is\,W = 2.303nRT\,{\log _{10}}\frac{{{P_D}}}{{{P_A}}}$
$ = 2.303 \times 2\,R \times 300\,{\log _{10}}\frac{{1 \times {{10}^5}}}{{2 \times {{10}^5}}} = - 414R$
Therefore work done on the gas is $+414\,R.$
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