\({R_1}\, = \,\,\,10\,\Omega ,\,\,{R_2}\,\, = \,\,30\,\,\Omega \) મૂકતાં
\(\frac{{10}}{{30}}\,\, = \,\,\frac{{{{l}_1}}}{{100 - {{l}_1}}}\)
\(\therefore \,\,\,30{{l}_1}\,\, = \,\,1000\,\, - \,\,10{{l}_1}\)
\(\therefore \,\,\,{{l}_1}\,\, = \,\,25\,\,\) સેમી
હવ, અવરોધોની અદલા બદલી કરતાં \(R_1 = 30\, \Omega , R_2 = 10\, \Omega\)
\(\therefore \,\,\frac{{30}}{{10}}\,\, = \,\,\frac{{{{l}_2}}}{{100 - {{l}_2}}}\)
\(\,\therefore \,\,300\,\, - \,\,3{{l}_2}\,\, = \,\,{{l}_2}\,\,\,\)
\(\,\therefore \,{{l}_2} = \,\,75\) સેમી
તેથી તટસ્થ બિંદુ \(75 - 25 = 50\) સેમી ખસશે.