$P V^{\gamma}=$ constant
or
$\frac{P_{1}}{P_{2}}=\left(\frac{V_{2}}{V_{1}}\right)^{\gamma}$
or
$P_{2}=2^{\gamma} P_{1}$
Now, for a monoatomic gas, the value of $\gamma$ is the highest
Thus, for the same change in volume, the monoatomic gas will have the maximum pressure.

