\(\therefore \) \(\frac{-d[{{H}_{2}}]}{dt}=\frac{3}{2}\frac{d[N{{H}_{3}}]}{dt}\)
\(\, = \frac{3}{2}\, \times \,2\, \times \,{10^{ - 4}}\)
\(3 \times 10^{-4 }\) મોલ.લિટર \(^{-1}.\) સેકન્ડ \(^{-1}\)
| No | $[A_2]\, M$ | $[B_2]\, M$ | rate of reaction |
| $1.$ | $0.1\,M$ | $0.1\,M$ | $1.6 \times {10^{ - 4}}$ |
| $2.$ | $0.1\,M$ | $0.2\,M$ | $3.2 \times {10^{ - 4}}$ |
| $3.$ | $0.2\,M$ | $0.1\,M$ | $3.2 \times {10^{ - 4}}$ |
$2NO \rightleftharpoons {N_2}O + \left[ O \right]$
${O_3} + \left[ O \right] \to 2{O_2}\,(slow)$
તો પ્રકિયાનો કમ જણાવો.
ખોટું વિધાન ઓળખો.
$log$નો ગુણધર્મ $\ln \left(\frac{{x}}{{y}}\right)=\ln {x}-\ln {y}$