\(\therefore \) \(\frac{-d[{{H}_{2}}]}{dt}=\frac{3}{2}\frac{d[N{{H}_{3}}]}{dt}\)
\(\, = \frac{3}{2}\, \times \,2\, \times \,{10^{ - 4}}\)
\(3 \times 10^{-4 }\) મોલ.લિટર \(^{-1}.\) સેકન્ડ \(^{-1}\)
$ O_3 $ $\rightleftharpoons$ $ O_2 + O$ ...... (ઝડપી) ;
$O + O_3 \rightarrow 2O_2$ ...... (ધીમી)
$\left[\right.$ આપેલ $\left.\mathrm{R}=8.314 \,\mathrm{JK}^{-1} \,\mathrm{~mol}^{-1}\right]$