$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
જો બંધ પાત્રમાં $0.1 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{NO}_{(\mathrm{g})}$ લેવામાં આવે તો, સંતુલન ૫૨ $\mathrm{NO}_{(\mathrm{g})}$ નો વિયોજન અંશ $(\alpha)$ શું થશે?
\(\mathrm{K}_{\mathrm{c}} \)\( =\frac{\left[\mathrm{N}_2\right]\left[\mathrm{O}_2\right]}{[\mathrm{NO}]^2} \)
\( =\frac{3 \times 10^{-3} \times 4.2 \times 10^{-3}}{2.8 \times 10^{-3} \times 2.8 \times 10^{-3}} \)
\( =1.607\)
\(2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \)
\(\mathrm{t}=0 \)
\(0.1 \quad 0 \quad 0 \)
\(0.1-0.1 \alpha \quad 0.05 \alpha \quad 0.05 \alpha \)
\(\mathrm{K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{(0.1-0.1 \alpha)^2} \)
\(\mathrm{~K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{0.01(1-\alpha)^2} \)
\(1.607=\frac{(0.05)^2 \alpha^2}{0.01(1-\alpha)^2} \)
\(\frac{\alpha^2}{(1-\alpha)^2}=\frac{1.607 \times(0.1)^2}{(0.05)^2} \)
\(\frac{\alpha}{1-\alpha}=\frac{1.27 \times 0.1}{0.05} \)
\(\frac{\alpha}{1-\alpha}=2.54 \)
\(\alpha=2.54-2.54 \alpha \)
\(3.54 \alpha=2.54 \)
\(\alpha=\frac{2.54}{3.54}=0.717\)
$PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$
જો સંતુલને પ્રક્રિયા મિશ્રણનું કુલ દબાણ $P$ હોય અને $PCl_5$ નો વિયોજન અંશ $x$ તો $PCl_3$ નું આંશિક દબાણ ......... થશે.
$2S{O_2} + {O_2}$ $\rightleftharpoons$ $2S{O_3} + Q$ $Cal$