$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
જો બંધ પાત્રમાં $0.1 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{NO}_{(\mathrm{g})}$ લેવામાં આવે તો, સંતુલન ૫૨ $\mathrm{NO}_{(\mathrm{g})}$ નો વિયોજન અંશ $(\alpha)$ શું થશે?
\(\mathrm{K}_{\mathrm{c}} \)\( =\frac{\left[\mathrm{N}_2\right]\left[\mathrm{O}_2\right]}{[\mathrm{NO}]^2} \)
\( =\frac{3 \times 10^{-3} \times 4.2 \times 10^{-3}}{2.8 \times 10^{-3} \times 2.8 \times 10^{-3}} \)
\( =1.607\)
\(2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \)
\(\mathrm{t}=0 \)
\(0.1 \quad 0 \quad 0 \)
\(0.1-0.1 \alpha \quad 0.05 \alpha \quad 0.05 \alpha \)
\(\mathrm{K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{(0.1-0.1 \alpha)^2} \)
\(\mathrm{~K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{0.01(1-\alpha)^2} \)
\(1.607=\frac{(0.05)^2 \alpha^2}{0.01(1-\alpha)^2} \)
\(\frac{\alpha^2}{(1-\alpha)^2}=\frac{1.607 \times(0.1)^2}{(0.05)^2} \)
\(\frac{\alpha}{1-\alpha}=\frac{1.27 \times 0.1}{0.05} \)
\(\frac{\alpha}{1-\alpha}=2.54 \)
\(\alpha=2.54-2.54 \alpha \)
\(3.54 \alpha=2.54 \)
\(\alpha=\frac{2.54}{3.54}=0.717\)
$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ માટે સંતુલન અચળાંક ......... થશે.
$Cu ^{2+}+ NH _{3} \stackrel{ K _{1}}{\rightleftharpoons}\left[ Cu \left( NH _{3}\right)\right]^{2+}$
$\left[ Cu \left( NH _{3}\right)\right]^{2+}+ NH _{3} \stackrel{ K _{2}}{\rightleftharpoons}\left[ Cu \left( NH _{3}\right)_{2}\right]^{2+}$
$\left[ Cu \left( NH _{3}\right)_{2}\right]^{2+}+ NH _{3} \stackrel{ K _{3}}{\rightleftharpoons}\left[ Cu \left( NH _{3}\right)_{3}\right]^{2+}$
$\left[ Cu \left( NH _{3}\right)_{3}\right]^{2+}+ NH _{3} \stackrel{ K _{4}}{\rightleftharpoons}\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$
$K _{1}, K _{2}, K _{3}$ અને $k_4$ ના સ્થિરતાં અચળાંકોનાં મૂલ્ય અનુક્રમે $10^{4}, 1.58 \times 10^{3}, 5 \times 10^{2}$ અને $10^2$ છે.$\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$ ના વિયોજન માટે સમગ્ર (બધાજ) સંતુલન અચળાંકો $x \times 10^{-12}$ છે. તો $x$ નું મૂલ્ય .......... છે. (નજીકનાં પૂર્ણાંકમાં રાઉન્ડ ઑફ)
$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
જો બંધ પાત્રમાં $0.1 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{NO}_{(\mathrm{g})}$ લેવામાં આવે તો, સંતુલન ૫૨ $\mathrm{NO}_{(\mathrm{g})}$ નો વિયોજન અંશ $(\alpha)$ શું થશે?
$\mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0$
$\mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0$
$\mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0$
$\mathrm{x} \rightleftharpoons \mathrm{w}$ પ્રક્રિયા માટે સંતુલન અયળાંક શોધો.