\(\frac{1}{2} m v^2+\frac{1}{2} I \omega^2=M g h\)
\(\frac{1}{2} M v^2+\frac{1}{2} I\left(\frac{v}{R}\right)^2=M g\left(\frac{3 v^2}{4 g}\right)\left(\because \omega=\frac{v}{R}\right)\)
\(\frac{1}{2} I \frac{v^2}{R^2}=\frac{3}{4} M v^2-\frac{1}{2} M v^2=\frac{1}{4} M v^2\)
\(I=\frac{1}{2} M R^2\)
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