\(V_{i}=60 \mathrm{V}\)

Zener voltage \(V_{z}=10 \mathrm{V}\) \(R_{L}=2 \mathrm{k} \Omega=2 \times 10^{3} \Omega\)

Load current, \(I_{\mathrm{L}}=\frac{V_{Z}}{R_{L}}=\frac{10}{2 \times 10^{3}}=5 \mathrm{\,mA}\)

Current through \(R, I=\frac{V_{i}-V_{Z}}{R}\)

\(=\frac{60-10}{4 \times 10^{3}}=\frac{50}{4 \times 10^{3}}=12.5 \mathrm{\,mA}\)

Fom circuit diagram,

\(I=I_{z}+I_{L}\)

\(\Rightarrow 12.5=I_{z}+5\)

\(\Rightarrow I_Z\,=\,12.5-5\,=\,7.5\,mA\)