\( = \,\,\frac{{13.12}}{5}\,\, = \,\,2.624\,\, \cong \,\,2.62\)
\(\begin{gathered}
\left( 1 \right)\,\,2.62\,\, - \,\,2.63\,\, = \, - 0.01 \hfill \\
\left( 2 \right)\,\,2.62\,\, - \,\,2.56\,\, = \,\, + 0.06 \hfill \\
\left( 3 \right)\,\,2.62\,\, - \,\,2.42\,\, = \,\, + \;\,0.20 \hfill \\
\left( 4 \right)\,\,2.62\,\, - \,\,2.71\,\, = \,\, - 0.09 \hfill \\
\left( 5 \right)\,\,2.62\,\, - \,\,2.80\,\, = \,\, - 0.18 \hfill \\
\end{gathered} \)
સરેરાશ નિરપેક્ષ ત્રુટિ \( = \frac{{0.01\,\, + \;\,0.06\,\, + \;\,0.20\,\, + \;\,0.09\,\, + \;\,0.18}}{5}\,\)
\( = \frac{{0.54}}{5}\,\, = \,\,0.108\,\, \cong \,\,0.11s\)
કારણ: $\frac{{\Delta E}}{E} = \frac{{\Delta m}}{m} + \frac{{2\Delta v}}{v}$
જ્યાં $X = \frac{{{A^2}{B^{\frac{1}{2}}}}}{{{C^{\frac{1}{3}}}{D^3}}}$