the voltmeter with resistance $R_{v}=120$ ohm and resistor $R_{2}=60$

ohm are in parallel, hence equivalent resistance between them is

$R_{e}=\frac{R_{2} R_{v}}{R_{2}+R_{v}}$

$R_{e}=\frac{(60)(120)}{60+120}=40 \Omega$

Now the reading of voltmeter can be obtain by

$V_{v}=V\left(\frac{R_{e}}{R_{1}+R_{e}}\right)$

$V_{v}=120\left(\frac{40}{60+40}\right)$

$V_{v}=40\left(\frac{6}{5}\right)=48 \mathrm{V}$