$H - H$ બંધઊર્જા | $:\, 431.37 \,kJ\, mol^{-1}$ |
$C= C$ બંધઊર્જા | $:\, 606.10\, kJ \,mol^{-1}$ |
$C - C$ બંધઊર્જા | $:\, 336.49\, kJ\, mol^{-1}$ |
$C - H$ બંધઊર્જા | $:\, 410.50\, kJ\, mol^{-1}$ |
પ્રક્રિયા : $\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{C = C} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\, + \,H - H\, \to \,\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{H - C - C - H} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\,$
$\Delta H = - 98.7\,{\mkern 1mu} kJ{\mkern 1mu} {\mkern 1mu} S{O_3} + {H_2}O \to {H_2}S{O_4};\Delta H = - 130.2{\mkern 1mu} \,kJ;$
${H_2} + \frac{1}{2}{\mkern 1mu} {O_2} \to {H_2}O;{\Delta _H} = - 287.3{\mkern 1mu} \,kJ$
તો $298\, K$ એ $H_2SO_4$ ની નિર્માણ એન્થાલ્પી ............. $\mathrm{kJ}$ માં શોધો.