\(A B \Rightarrow S=6 t_1=24 t \Rightarrow t_1=4 t\)
\(<\text { speed }>=\frac{\text { dist. }}{\text { time }}=\frac{48 t}{2 t+t_1}\)
\(=\frac{48 t}{2 t+4 t} \Rightarrow \frac{48 t}{6 t} \Rightarrow 8 \mathrm{~m} / \mathrm{s}\)
$\left[ g =10 \,ms ^{-2}\right.$ લો.$]$