MCQ
${\sin ^{ - 1}}\left[ {{{\log }_3}\left( {\frac{x}{3}} \right)} \right]$ નો પ્રદેશ મેળવો.
- ✓$[1, 9]$
- B$[-1, 9]$
- C$[-9, 1]$
- D$[-9, -1]$
==> $ - 1 \le {\log _3}\left( {\frac{x}{3}} \right) \le 1$
==> $\frac{1}{3} \le \frac{x}{3} \le 3$ ==> $1 \le x \le 9$ ==> $x \in [1,\,9]$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.