MCQ
$\sin \left( {2{{\tan }^{ - 1}}\left( {\frac{1}{3}} \right)} \right) + \cos ({\tan ^{ - 1}}2\sqrt 2 ) = $
  • A
    $\frac{{16}}{{15}}$
  • $\frac{{14}}{{15}}$
  • C
    $\frac{{12}}{{15}}$
  • D
    $\frac{{11}}{{15}}$

Answer

Correct option: B.
$\frac{{14}}{{15}}$
(b) $\sin \left[ {2{{\tan }^{ - 1}}\left( {\frac{1}{3}} \right)} \right] + \cos \,[{\tan ^{ - 1}}(2\sqrt 2 )]$

$= \sin \left[ {{{\tan }^{ - 1}}\frac{{2/3}}{{1 - 1/9}}} \right] + \cos \,[{\tan ^{ - 1}}(2\sqrt 2 )]$

$ = \sin [{\tan ^{ - 1}}3/4] + \cos \,[{\tan ^{ - 1}}2\sqrt 2 ]$

$ = \frac{3}{5} + \frac{1}{3} = \frac{{14}}{{15}}$.

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