$\frac{{\log \,\,{K_2}}}{{\log \,\,{K_1}}}\, = \,\frac{{ - \,{E_a}}}{{2.303\,R}}\left( {\frac{1}{{{T_2}}}\, - \,\frac{1}{{{T_1}}}} \right)$

Given $\frac{{\log \,\,{K_2}}}{{\log \,\,{K_1}}}\, = 2$  $T_2\,=\,308$:  $T_1\,=\,298$

$\therefore \,\,\log \,\,2\,\, = \frac{{ - \,{E_a}}}{{2.303\, \times 8.314}}\left( {\frac{1}{{308}}\, - \,\frac{1}{{298}}} \right)$

${E_a}\, = \,52.9\,\,kJ\,\,mo{l^{ - 1}}$