The amplification factor of a triode is $18$ and its plate resistance is $8 \times 10 \Omega$. A load resistance of $10 \Omega$ is connected in the plate circuit. The voltage gain will be
A$ 30$
B$ 20$
C$10$
D$1$
[RPMT 2002]
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C$10$
$\text { Voltage gain } A_v=\frac{\mu}{1+\frac{r_p}{R_L}}=\frac{18}{1+\frac{8 \times10^3}{10^4}}=10 .$
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