The amplitude of a particle executing S.H.M. with frequency of 60… - Vidyadip

MCQ

The amplitude of a particle executing $S.H.M.$ with frequency of $60 \,Hz$ is $0.01 \,m$. The maximum value of the acceleration of the particle is

✓
$144{\pi ^2}\,m/se{c^2}$
B
$144\,m/se{c^2}$
C
$\frac{{144}}{{{\pi ^2}}}\,m/se{c^2}$
D
$288{\pi ^2}\,m/se{c^2}$

✓

Answer

Correct option: A.

$144{\pi ^2}\,m/se{c^2}$

a
(a) Maximum acceleration $ = a{\omega ^2} = a \times 4{\pi ^2}{n^2}$

$ = 0.01 \times 4 \times {(\pi )^2} \times {(60)^2} = 144{\pi ^2}\,m/\sec $

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