The correct order of boiling point for primary (1), secondary (2) and tertiary (3) alcohols is:
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1 > 2 > 3
Explanation:
Alcohols with same molecular weight are expected to have almost same boiling point however two more factors other than molecular weight are important, they are namely H-bonding and surface area of molecule. Both these factors are least in 3 alcohols and maximum in 1 alcohols. Hence, 3 alcohols have least boiling point while 1 alcohols have maximum boiling point.
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When $3-$methylbutan$-2-$ol is treated with $\ce{HBr},$ the following reaction takes place. What are the correct steps for formation of the above product?
Which of the following is produced during the following reaction? $\text{CO(g)} + \text{H}_2\text{(g)}\xrightarrow[\text{ZnO}\text{Cr}_2\text{O}_3]{575\text{k}}$